-6x^2+11x+15=0

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Solution for -6x^2+11x+15=0 equation:



-6x^2+11x+15=0
a = -6; b = 11; c = +15;
Δ = b2-4ac
Δ = 112-4·(-6)·15
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{481}}{2*-6}=\frac{-11-\sqrt{481}}{-12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{481}}{2*-6}=\frac{-11+\sqrt{481}}{-12} $

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